4m^2+12m-13-39=0

Solution for 4m^2+12m-13-39=0 equation:

4m^2+12m-13-39=0

We add all the numbers together, and all the variables

4m^2+12m-52=0

a = 4; b = 12; c = -52;
Δ = b2-4ac
Δ = 122-4·4·(-52)
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{61}}{2*4}=\frac{-12-4\sqrt{61}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{61}}{2*4}=\frac{-12+4\sqrt{61}}{8}
$